Question-1 :-  Find : (i) 64^1/2  ,  (ii) 32^1/5  ,  (iii) 125^1/3

(i)   641/2
     =(2)6 x 1/2
     =23
     =8

(ii)  321/5
     =(2)5 x 1/5
     =21
     =2

(iii) 1251/3
     =(5)3 x 1/3
     =51
     =5
    

Question-2 :-  Find : (i) 9^3/2  ,  (ii) 32^2/5  ,  (iii) 16^3/4   ,  (iv) 125^-1/3

(i)   93/2
     =(3)2 x 3/2
     =33
     =27

(ii)  322/5
     =(2)5 x 2/5
     =22
     =4

(iii) 163/4
     =(2)4 x 3/4
     =23
     =8

(iv)  125-1/3
     =(5)3 x (-1/3)
     =5-1
     =1/5
    

Question-3 :-  Simplify : (i) 2^2/3 . 2^1/5  ,  (ii) (1/3³)⁷  ,  (iii) 11^1/2 ÷ 11^1/4  ,  (iv) 7^1/2 . 8^1/2

(i)   22/3. 21/5    
    = 2(2/3 + 1/5)    
    = 2(10+3)/15  
    = 213/15

(ii) (1/33)7
    = 1/(3)21
      
(iii) 111/2 ÷ 111/4
    = 11(1/2 - 1/4)
    = 11(2-1)/4
    = 111/4

(iv)  71/2 . 81/2
    = (7 x 8)1/2
    = 561/2